Question

A 0.50-kg croquet ball is initially at rest on the grass. When the ball is struck by a mallet, the average force exerted on it is 270 N .?

Answer 1

Step-by-step explanation:

Given

mass of ball
`m=0.5\ kg`

when it is struck by a mallet then average force exerted is
`F_(avg)=270\ N`

suppose v is the velocity of ball after collision then

change in momentum of ball is given by

`\Delta P=m(v-0)=0.5\cdot v`

and impulse given by change in momentum of object when an force is applied for a period of time

if t is the time of contact

`F_(avg)* t=\Delta P`

`t=(\Delta P)/(F_(avg))`

`t=(270)/(0.5\cdot v)`

`t=(540)/(v)`

Now velocity after impact v=3\ m/s

`t=(540)/(3)`

`t=180\ s`