Question

Please help!!

The perimeter of Rectangle A is three times that of Rectangle B. Rectangle B
is 4 cm long and 6 cm wide. Given that Rectangle A and Rectangle B are
similar, what is the perimeter of Rectangle A?
A. 72 cm
B. 60 cm
C. 20 cm
D. 24 cm

Answer 1

Explanation:

Rectangle B :

P = 2(L + W)

L = 4

W = 6

P = 2(4 + 6).....P = 2(10)...P = 20 cm

so the perimeter of rectangle B is 20 cm

perimeter of rectangle A is 3 times bigger...

so perimeter of rectangle A is : (3 * 20) = 60 cm <==

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another way to do this is if rectangle A is 3 times bigger, then the length and width are 3 times bigger too

so if rectangle B has a length of 4 cm, then rectangle A has a length of

(4 * 3) = 12 cm

and if rectangle B has a width of 6 cm, then rectangle A has a width of

(6 * 3) = 18 cm

so rectangle A perimeter is :

P = 2(L + W)

L = 12

W = 18

P = 2(12 + 18)...P = 2(30).....P = 60 cm <===

either way u choose to do it will give u the same answer