Question

I need help plz

The system of linear equations 5 x + 3 y = 3 and x + y = negative 1 is graphed below.

What is the solution to the system of equations?
(–4, 3)
(–3, 4)
(3, –4)
(4, –3)

Answer 1

C

Explanation:

Answer 2

The solution for given linear equation systems is (3,-4).

Option: C

Explanation:

The given equations are 5x+3y=3 and x+y= -1.

Let us isolate x value from equation 5x+3y=3.

5x = 3-3y.

`x=(3-3y)/(5)`.

Substitute this x value in equation x+y= -1.

`(3-3y)/(5)+y=-1`.

After taking LCM for the denominator,

`(3-3y+5y)/(5)= -1`.

3-3y+5y=-5.

2y=-8.

y=-4.

For
`x=(3-3y)/(5)` substitute the y value.

`x=(3-3(-4))/(5)`.

`x=(3+12)/(5)`.

`x=(15)/(5)`.

x=3.

∴ The solution is (3,-4).