Question

Miguel will rent a car for the weekend he can choose one or two plans the first one has no initial favorite cost $.70 per mile driven the second plan as an initial fee of $75 in cost an additional $.60 per mile driven how many miles with MIQUEL need to drive for the two plans to cost the

Answer 1

Explanation:

The first plan has no initial fee. If the unknown is the number of miles driven, then the equation for the first plan is

C(x) = .7x

The second plan has a fee plus mileage, so with the unknown again being the number of miles driven, then the equation for the second plan is

C(x) = .6x + 75

If we are looking to solve for the number of miles when the cost is the same, we set the cost functions equal to each other and solve for x:

.7x = .6x + 75 and

.1x = 75 so

x = 750

This is really a very helpful thing to be able to figure out, because if you use the first plan and want to drive MORE than the 750 miles, you will be paying more than if you want to drive more than the 750 miles and choose the second plan. For miles less than 750 plan one is cheaper, for miles greater than 750 plan two is cheaper.

See, there really IS a reason for all this algebra!!