226k views
2 votes
A passenger jet flies from one airport to another 1273 miles away in 2.7 h. Find its average speed.​

User Bisamov
by
5.7k points

1 Answer

5 votes

Answer:

Average speed of passenger jet


s = 471.48\ mi/hr

Step-by-step explanation:

Let s be the average speed of the passenger jet.

Given:

Distance from one airport to another airport
d = 1273\ mi

Total time taken
t = 2.7\ hr

We need to find the average speed of the passenger jet.

Solution:

Average speed formula:

The ratio of the total distance travelled by the object to the time taken to cover that distance.


Average\ speed = (Total\ distance\ travelled)/(Total\ time\ taken)


s = (d)/(t)

Substitute total distance and time value in above equation.


s = (1273)/(2.7)


s = 471.48\ mi/hr

Therefore, the average speed of the passenger jet is
s = 471.48\ mi/hr.

User Dave Chambers
by
5.3k points