Question

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ Answer

Answer 1

For what? Sorry is there an attachment?

Answer 2

-0.4

Explanation:

We are given that an interval [-3,2] and the values of function h(t) given

We have to find the average rate of change of h(t) over the interval [-3,2].

We know that

Average rate of change of function f(x) on interval [a,b] is given by

Average rate of change of f(x)
`=(f(b)-f(a))/(b-a)`

h(t) at t=-3

h(t)=2

at t=2

h(t)=0

Using the formula

Average rate of change of h over interval [-3,2]=
`(0-2)/(2-(-3))`

Average rate of change of h over interval [-3,2]=
`-(2)/(2+3)=-(2)/(5)`

Average rate of change of h over interval [-3,2]=-0.4