Answer:
Part 1) the linear equation is
![y=1.75x+16](https://img.qammunity.org/2021/formulas/mathematics/middle-school/z6st574szj6cuz1rwi2c011ap9kultwlvs.png)
Part 2) The graph in the attached figure
Explanation:
Part 1) Write an equation
Let
x ----> the time in seconds
y ----> the distance in feet that the kite is from the end of your hands
we know that
The linear equation in slope intercept form is equal to
![y=mx+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yj5waqmoy4i54laybzhhshd88hyo5w5rj5.png)
where
m is the slope or unit rate of the linear equation
b is the y-intercept or initial value
In this problem
we have
![m=1.75\ (ft)/(sec)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/dml0dorau6142sbplu60bmhhlid8vmdk22.png)
![point\ (8,30)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ba2mdbjept927t8jscgd446taewz8clt2e.png)
substitute
![30=1.75(8)+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/k0upg9y1vzrxo0toi4uzwafk6sb0urhses.png)
solve for b
![30=14+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nt0kuyp5y9bgkybzseo609g9v54c75atzd.png)
![b=30-14](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ifvu7rqnx4cb2ipxdoptga8d7klk87m7xw.png)
----> the initial distance
therefore
The linear equation is equal to
![y=1.75x+16](https://img.qammunity.org/2021/formulas/mathematics/middle-school/z6st574szj6cuz1rwi2c011ap9kultwlvs.png)
Part 2) Graph the equation
we have
![y=1.75x+16](https://img.qammunity.org/2021/formulas/mathematics/middle-school/z6st574szj6cuz1rwi2c011ap9kultwlvs.png)
To graph the line we need two points
we have
(0,16) and (8,30)
Plot the points and connect them to graph the line
Remember that the values of x and y cannot be a negative number
The graph in the attached figure