5 yards of fence can be secure with 1 lb of nails
Solution:
Given that Mr. Adams used 2/3 lbs of nails to secure 3 & 1/3 yards of fence
To find: yards of fence can mr Adams Secure with 1 lb of nails
From given statement,


Thus we can say,

Let "x" be the yards of fence secure with 1 lb of nails
Then we get,

This forms a proportion and we can solve the sum by cross multiplying

Thus 5 yards of fence can be secure with 1 lb of nails