Answer:
New computer will take 33.28 hours to complete the calculation by itself.
Explanation:
Let the time taken by the new computer to complete the calculation = x hours
Per hours work done by the new computer =

Time taken by the older computer to complete the calculation = (x + 11) hour
Per hour work done by old computer =

When both the computers work together they complete the work in 19 hours.
Therefore, per hour work done by both together =

We per hour work done by both individually = per hour work done by both together



38x + 209 = x² + 11x
x² - 27x - 209 = 0
By quadratic formula,
x =

x =

x =

x =

x = 33.28 hours
Therefore, new computer will take 33.28 hours to complete the calculation by itself.