Question

Which is the answers

Answer 1

below

Explanation:

1. Area for Face A (the square)

Formula: A=a^2

A = Area, a = side

Fill in:

A = 7^2

Solve:

7 ^2, aka 7 x 7 = 49

2. Area for Face B (the flat triangles)

Formula: A = 1/2 × b × h

b = base, h = height

Fill in:

A = 1/2 × 7 × 10

Solve:

(Multiplying by 1/2 is the same as dividing by 2)

A = 1/2 x 7 x 10
7 × 10 = 70

divide by 2

70/2 = 35

Now we count how many Face B triangles there are, and add the area of each one together:

# of Face B Triangles: 4

multiply it by 35, or just add 35 4 times: 140

3. Total Surface Area for Pyramid:

Base Surface Area = 7^2 = 49

Lateral Surface Area = 2 × 7 × √(7/2)^2 + 10^2 =148.32734070292

Total Surface Area = 197.32734070292

Answer 2

1. 49

2. 35

3. 4

4. 140

5. 189

Explanation:

1. Face A is a square with a height of 7 cm, so the length and width have to be 7 too. 7*7=49.

2. area=base*height/2. The base is 7, the height is 10, their product is 70. 70/2=35.

3. In the net, 4 traingles labeled B are present

4. area of b triangles*number of b triangles: 35*4=140

5. square+b triangles=surface area. 49+140=189.