Question

SOMEONE PLEASE HELP ME ASAP PLEASE!!!!​

Answer 1

Therefore,

`a_(21)=2`

Explanation:

Given:

`A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]`

To Find:

a₂₁ = ?

Solution:

Let,

`A=\left[\begin{array}{ccc}a_(11)&a_(12)&a_(13)\\a_(21)&a_(22)&a_(23)\\\end{array}\right]`

We require ' a₂₁ ' i.e Second Row First Column Element

So on Comparing we get

∴
`a_(21)=2`

Therefore,

`a_(21)=2`