The solution to given system of equations are (x, y) = (4, 2)
Solution:
Given system of equations are:
2x + 3y = 14 ---------- eqn 1
3x - 4y = 4 --------- eqn 2
We have to solve the given system of equations
We can solve the above system of equations by elimination method
Multiply eqn 1 by 3
3(2x + 3y = 14)
6x + 9y = 42 --------- eqn 3
Multiply eqn 2 by 2
2(3x - 4y = 4)
6x - 8y = 8 ----------- eqn 4
Subtract eqn 4 from eqn 3
6x + 9y = 42
6x - 8y = 8
( - ) --------------
9y + 8y = 42 - 8
17y = 34
y = 2
Substitute y = 2 in eqn 1
2x + 3(2) = 14
2x + 6 = 14
2x = 14 - 6
2x = 8
x = 4
Thus the solution to given system of equations are (x, y) = (4, 2)