Question

The perimeter of a rectangle field is 118m.if the length of rectangle is 7m less than twice the width ,what is the length of the field

Answer 1

Length = 37 m.

Explanation:

Perimeter P = 2L + 2W where L = length and W = the width.

L = 2W - 7 (given)

118 = 2L + 2W

Substituting for L:

118 = 2(2W - 7) + 2W

4W - 14 - 2W = 118

6W = 118 + 14 = 132

W = 132/6 = 22.

So L = 2*22- 7 = 37 m.

Answer 2

length = 37 m

Explanation:

let w be width then length = 2w - 7

The opposite sides of a rectangle are congruent

The perimeter is the sum of the 4 sides and is equal to 118 , then

w + w + 2w - 7 + 2w - 7 = 118 , that is

6w - 14 = 118 ( add 14 to both sides )

6w = 132 ( divide both sides by 6 )

w = 22

Then

length = 2w - 7 = 2(22) - 7 = 44 - 7 = 37 m