Question

Liz has 2 blue, 1 red and 1 white dress(es) and 3 pairs of shoes colored blue, red and white. If she decides at random what to wear, what are the probabilities of wearing:

Shoes and a dress that is both not white

Answer 1

11/12

Explanation:

Let's go:

Liz doesn't wear white dress and shoes. But If she want's, she does white dress and another shoes, like blue. That's possible.

It's only option who Liz doesn't wear: are both white.

4 × 3 = 12

Then, the probability of wearing dress and shoes both white is 1/12.

So, the probability of don't wear dress and shoes both white is:

12/12 - 1/12 = 11/12

I hope I've helped you.

I hope you've understood, too.