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Write (d+5)+(d+5)+(d+5)+(d+5) as an equivalent expression by grouping the like terms

User Daniel Lin
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1 Answer

1 vote

Answer:


4(d+5)

Explanation:


(d+5)+(d+5)+(d+5)+(d+5)

There is 4 times (d+5), or
4(d+5).

You can also do it like this:


(d+5)+(d+5)+(d+5)+(d+5)


(d+d+d+d)+(5+5+5+5)


4d+20


4(d+5)

User Jason Maskell
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