The length of side a is 36 feet and side b is 18 feet and side c is 39 feet
Solution:
Given that length of triangle is 93 feet
Thus, perimeter of triangle = 93 feet
The three sides of triangle are a, b, and c
Side a of the triangle is twice as long as side b
side a = 2 times side b
a = 2b
---- eqn 1
Given that Side c is 3 ft longer than side a
side c = 3 + side a
c = 3 + a ------ eqn 2
The perimeter of triangle is given as:
p = a + b + c
Where a, b, c are the length of sides of triangle
Substitute eqn 1 and eqn 2 in above formula
![p = a + (a)/(2) + 3 + a](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hbolrluqup8dokfewdmmsvo61huxy0lkmr.png)
Given that perimeter = 93
![93 = a + (a)/(2) + 3 + a\\\\93 = (2a + a + 6 + 2a)/(2)\\\\93 * 2 = 2a + a + 6 + 2a\\\\186 = 5a + 6\\\\5a = 186 - 6\\\\5a = 180\\\\a = 36](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hvb1waaoa1ahx4uxvaatpharma8gcugf8w.png)
Thus length of side a = 36 feet
Length of side b :
from eqn 1
![b = (36)/(2) = 18](https://img.qammunity.org/2021/formulas/mathematics/middle-school/u5r4kp3g3fvyfmhkmvsupvri7ok7sqw6qv.png)
b = 18 feet
Length of side c:
From eqn 2,
c = 3 + 36 = 39
c = 39 feet
Thus length of side a is 36 feet and side b is 18 feet and side c is 39 feet