Question

If x = 3 in. and y = 4 in., what is the perimeter of the polygon? in

Answer 1

86 in

Explanation:

We are given that

x=3in and y=4 in

Sides of polygon are

`4y,4x^2-3y^2,3x,x^2+2y^2,2y^2`

We have to find the perimeter of polygon.

Perimeter of polygon=Sum of all sides of polygon

Perimeter of polygon=
`4y+4x^2-3y^2+3x+x^2+2y^2+2y^2=5x^2+y^2+3x+4y`

Substitute the values of x and y

Then, we get

Perimeter of polygon=
`5(3)^2+(4)^2+3(3)+4(4)`

Perimeter of polygon=86 in

Hence, the perimeter of polygon=86 in