91.3k views
4 votes
If the envelope and gondola have a total mass of 4300 kg, what is the maximum cargo load when the blimp flies at a sea-level location? Assume an air temperature of 20∘C.

2 Answers

6 votes

Final answer:

To find the maximum cargo load when the blimp flies at a sea-level location, we need to use Archimedes' Principle and the concept of buoyancy. The maximum cargo load can be calculated by subtracting the mass of the envelope and gondola from the lifting capacity of the blimp.

Step-by-step explanation:

To find the maximum cargo load when the blimp flies at a sea-level location, we need to use Archimedes' Principle and the concept of buoyancy. The maximum cargo load can be calculated by subtracting the mass of the envelope and gondola from the lifting capacity of the blimp.

Lifting capacity = (Mass of cool air displaced by the blimp) - (Mass of gas in the blimp)

Since the lifting capacity is equal to the difference in the mass of cool air displaced by the blimp and the mass of the gas in the blimp, we can find the maximum cargo load by subtracting the combined mass of the envelope and gondola from the lifting capacity. Given that the total mass of the envelope and gondola is 4300 kg, the maximum cargo load would be the lifting capacity minus the total mass: Maximum cargo load = Lifting capacity - 4300 kg.

User Jurakin
by
6.8k points
3 votes

QUESTION: The question is incomplete. See the complete question below and the answer.

The classic Goodyear blimp is essentially a helium balloon— a big one, containing 5700 m3 of helium. If the envelope and gondola have a total mass of 4300 kg, what is the maximum cargo load when the blimp flies at a sea-level location? Assume an air temperature of 20°C.

Answer:

Mass of the cargo load = 1548.2kg

Step-by-step explanation:

Calculating the weight of helium gas, we have

W = mg

= (pv)g

=(0.178 * 5700)g

=(1014.6)g

Weight of envelope and gondola;

W = (4300kg)g

Weight of cargo load = mg (unknown)

The upthrust force on the balloon is calculated as;

F =pvg

= (1.204 *5700)g

=(6862.8)g

But;

Weight of helium gas + weight of envelope and gondola + weight of cargo = upthrust force on the balloon.

Substituting, we have;

(1.0146)g + (4300kg)g + mg = (6862.8)g

mg = (6862.8)g - (1014.6)g - (4300kg)g

mg = (1548.2kg)g

m = (1548.2kg)g/g

m = 1548.2kg

User Aditya Krishn
by
6.5k points