Question

A diver is on a board 3.00 m above the water . She jumps straight up at 3.25 m/s. . How many seconds later does she hit the water ?

Answer 1

1.18 sec

Step-by-step explanation:

v = 0

u = 3.25m/s

v = u - gt

t1 = u/g = 3.25/9.8 = 0.332 s

height above board = v²/2g =

3.25²/(2×9.8) = 0.54 m

time to fall from there to water

t2 = √(2h/g) = √(2(3+ 0.54)/9.8) = 0.85 s

total time = t1 + t2

total time = 0.85 + 0.332 = 1.182 s