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An IV order calls for the addition of 35 mEq of Calcium Carbonate. You have a 50 ml vial of CaCo3 4.4 mEq/ml. How many ml's of this concentrate do you need to add to this IV?

User RameshD
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Answer:

V = 7.95 mL

Step-by-step explanation:

We have in the 50 mL vial the next quantity of CaCO₃:


mEq CaCO_(3) = 4.4 (mEq)/(mL) \cdot 50 mL = 220 mEq

Knowing that in 50 mL we have 220 mEq of CaCO₃, to have 35 mEq we need the following volume of the concentrate (Vc):


V_(c) = (50 mL)/(220 mEq) \cdot 35 mEq = 7.95 mL

Therefore, for the addition of 35 mEq to the IV order, we need 7.95 mL of the concentrate 4.4 mEq/mL of CaCO₃.

I hope it helps you!

User Autokilled
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