Question

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Answer 1

The value of given function

A) f(0) = 0

B) f(18) = 9

C) f( - 18) = - 9

Explanation:

Given as :

The function of x is given as

f(x) =
`(x)/(2)`

So, for every value of x , the value of function of x changes

A) for x = 0

f(0) =
`(0)/(2)`

i.e f(0) = 0

B) for x = 18

f(18) =
`(18)/(2)`

i.e f(18) = 9

C) for x = - 18

f( -18) =
`( -18)/(2)`

i.e f(-18) = - 9

So, The value of f(0) = 0 , f(18) = 9 , f( - 18) = - 9

Hence, The value of given function

A) f(0) = 0

B) f(18) = 9

C) f( - 18) = - 9 Answer

Answer 2

The values for the given function f is defined by
`f(x)=(1)/(2)x` is

a)
`f(0)=0` ,

b)
`f(18)=9` and

c)
`f(-18)=-9`

Explanation:

Given that the function f is defined by
`f(x)=(1)/(2)x`

Now to find the value of f(0), f(18) and f(-18)

Now take f(0)

Put x=0 in the given function
`f(x)=(1)/(2)x` we get

`f(0)=(1)/(2)(0)`

`=0`

Therefore
`f(0)=0`

Put x=18 in the given function
`f(x)=(1)/(2)x` we get

`f(18)=(1)/(2)(18)`

`=9`

Therefore
`f(18)=9`

Put x=-18 in the given function
`f(x)=(1)/(2)x` we get

`f(-18)=(1)/(2)(-18)`

`=-9`

Therefore
`f(-18)=-9`

The values for the given function f is

a)
`f(0)=0` ,

b)
`f(18)=9` and

c)
`f(-18)=-9`