Question

Calculate [OH−] for a solution formed by adding 4.80 mL of 0.180 M KOH to 17.0 mL of 6.5×10−2 M Ca(OH)2.

Answer 1

To calculate [OH-], we need to consider the concentration of the solute and the fact that Ca(OH)2 is a strong base. By doubling the concentration, we get the actual [OH-].

Step-by-step explanation:

We begin by determining [OH]. The concentration of the solute is 0.0044 M, but because Ca(OH)2 is a strong base, there are two OH ions in solution for every formula unit dissolved, so the actual [OH] is two times this, or 2 × 0.0044 M = 0.0088 M. Now we can use the Kw expression: