Question

A pitcher draws back his arm 0.5 m and then pitches a 0.5 kg baseball at 40 m/s, releasing the ball 1 m in front of his body. What is the average force being applied by the pitcher?

Answer 1

F = 266.67 N

Step-by-step explanation:

given,

mass of the baseball = 0.5 Kg

speed of the baseball = 40 m/s

total displacement of the pitchers hand = 1 + 0.5 = 1.5 m

average force applied by the pitcher = ?

we know,

Work done is equal to change in kinetic energy, wheres as the initial velocity of the ball is zero.

W = KE

we know work done is equal to Force x displacement

`F .s = (1)/(2)mv^2`

`F* 1.5 = (1)/(2)* 0.5 * 40^2`

F x 1.5 = 400

F = 266.67 N

the average force being applied by the pitcher is equal to F = 266.67 N