Question

1. A curling stone has a mass of 45 kg. It has an initial speed of 1.1 m/s and travels 45 m to hit the target and come to a stop. Determine the coefficient of kinetic friction between the ice and the stone.

Answer 1

0.0013

Step-by-step explanation:

m = 45kg

s = 45m

u = 1.1m/s

v = 0

a = ?

g = 10m/s

using equation of motion to find the acceleration of the curling stone.

v² = u² + 2as

0² = 1.1² + 2a × 45

a = -0.013m/s (deceleration)

Fk = #R

# = a/g = 0.013/10 = 0.0013

NB: check the initial velocity in the question, i think its too small