Answer:
Option D. 5.5
Step-by-step explanation:
The equation is this:
2A + 6B ⇒ 3C
With the amounts that we were given, let's determine which is the limting reactant
2 A reacts with 6 B
4 A will react with ( 4 .6)/2 = 12B
I have 11 B, so the limiting is B
6 B react with 2 A
11 B will react with (11 .2 )/6 =3.66 A
I have 4 A, so A is the excess.
6 B produce 3 C
11 B will produce ( 11 .3)/6 = 5.5C