Question

T squared plus 5.4t plus 3.6 equals 0

Answer 1

The roots of the quadratic equation are.

t = -0.78

t = -4.62

Explanation:

Assume: we find the roots of the given quadratic equation.

Given:

the given expression is.

T squared plus 5.4t plus 3.6 equals 0

Rewrite the equation as.

`t^(2)+5.4t+3.6=0`

Now, we first find the root of the above equation.

Use quadratic formula with
`a=1, b=5.4, c=3.6`.

`t=\frac{-b\pm \sqrt{(b)^(2)-4ac}}{2a}`

Put a, b and c value in above equation.

`t=\frac{-5.4\pm \sqrt{(5.4)^(2)-4(1)(3.6)}}{2(1)}`

`t=(-5.4\pm √(29.16-4* 3.6))/(2)`

`t=(-5.4\pm √(29.16-14.4))/(2)`

`t=(-5.4\pm √(14.76))/(2)`

`t=(-5.4\pm 3.84)/(2)`

For positive sign

`t=(-5.4 + 3.84)/(2)`

`t=(-1.56)/(2)`

t = -0.78

For negative sign

`t=(-5.4 - 3.84)/(2)`

`t=(-9.24)/(2)`

t = -4.62

Therefore the roots of the quadratic equation t = -0.78 or t = -4.62

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