Question

Blocks with masses of 7.0 kg, 8.0 kg, and 9.0 kg are lined up in a row on a frictionless table. All three are pushed forward by a 20 N force applied to the 7.0 kg block.

1. ) How much force does the 8.0 kg block exert on the 9.0 kg block?

2.) How much force does the 8.0 kg block exert on the 7.0 kg block?

Answer 1

7.497 N

14.161 N

Step-by-step explanation:

m = Mass

a = Acceleration

Force is given by

`F=ma\\\Rightarrow a=(F)/(m)\\\Rightarrow a=(20)/(7+8+9)\\\Rightarrow a=0.833\ m/s^2`

For the 9 kg block

`F=ma\\\Rightarrow F=9* 0.833\\\Rightarrow F=7.497\ N`

The force on the 9 kg block is 7.497 N

Here m = 8+9 = 17 kg

`F=ma\\\Rightarrow F=17* 0.833\\\Rightarrow F=14.161\ N`

The force on the 7 kg block is 14.161 N