Answer:
Part 1)
Part 2)
a) The graph in the attached figure
b) The cost of each extra line is $5.25
c) The cost of one line the same as the cost of four lines
Part 3)
Explanation:
Part 1)
Let
x ----> the number of lines in the ad
y ----> the cost to run the ad for one week
we know that
The total cost to place a 6-line ad for one week is equal to sum the cost for one line ($42) plus the cost of 5 additional extra line ($6.75 per extra line)
so
The linear equation that represent this situation is
For x=6 lines
substitute
----> this is the cost for one week
To find out the cost for three weeks multiply by 3
Part 2) we have
when x≤ 4
when x>4
where
x is the number of lines in the ad
C(x) the cost of a classified ad
Part a) Graph the function
we know that
In the interval [0,4] the graph is a horizontal line (constant) C(x)=35.50
In the interval (4,∞) the graph is the linear equation C(x)=35.50+5.25(x-4)
using a graphing tool
The graph in the attached figure
Part b) Find out the cost of each extra line
we have
For x=5
so
The cost of each extra line is $5.25
Part c) Is the cost of one line the same as the cost of four lines?
we know that
when x≤ 4
so
For one line x=1
For four lines x=4
Both values belong to the interval [0,4]
therefore
The cost of one line the same as the cost of four lines
Part 3) we know that
To find out the amount of sales tax multiply the total amount by the percentage of sales tax
Remember that
so