Answer:
205.3 mL of ethyl alcohol
Step-by-step explanation:
The resulting container and liquid mixture has a mass of 512 g
Mass of container + Mass of water + Mass of ethyl alcohol
150 g + 200 g + Mass of ethyl alcohol = 512 g
We know that water has a mass of 200g, cause the density, which values 1 g/mL.
200 mL are contained in 200 g of water.
Mass of ethyl alcohol = 512 g - 200 g - 150 g ⇒ 162 g
Density of ethyl alcohol = ethyl alcohol mass / ethyl alcohol volume
0.789 g/mL = 162g / ethyl alcohol volume
162 g / 0.789 g/mL = 205.3 mL