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What is the exact value of arcsin(−√2/2) ?

Enter your answer, in terms of π , in the box.

User Simianarmy
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2 Answers

5 votes

Answer: -pi/4

Explanation:

What is the exact value of arcsin(−√2/2) ? Enter your answer, in terms of π , in the-example-1
User Moein Hosseini
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3.7k points
3 votes

Answer:5Π/4

Explanation:

arcsin(−√2/2) = -45°

Note that the angle is negative and according to quadrant, sine is negative at the 3rd and 4th quadrant.

In the 3rd quadrant, the equivalent angle is (180+theta) while at the 4th quadrant it is (360-theta.)

Using the 3rd quadrant which will give us the least value,

theta = 180+45

= 225° (note that the minus sign only tells us the quadrant sine falls into, hence we cant use the minus during addition)

therefore theta = 225°

Since 180° = Πrad

225° to rad = 225×Πrad/180

= 5Π/4 rad

User Lewiada
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3.5k points