Question

Suppose that a tank holds 2% liquid water by volume and 98% vapor water by volume at a pressure of 0.005 MPa. What is the quality?

Answer 1

The quality is 93%.

Step-by-step explanation:

Given that,

Pressure = 0.005 MPa

Liquid water = 2%

Vapor water = 98%

We need to calculate the quality

Using formula of quality

`quality=\frac{\text{Vapour water}*\text{specific volume of liquid water at 0.005}}{\text{Liquidr water}*\text{specific volume of vapour water at 0.005}}`

Put the value into the formula

`quality=(98*0.0010)/(5*2.08719)`

`quality=0.0093`

`quality=0.0093*100`

`quality=93\%`

Hence, The quality is 93%.