Question

22.5 mL of an HNO3 solution were titrated with 31.27 mL of a .167 M NaOH solution to reach the equivalence point. What is the molarity of the HNO3 solution

Answer 1

Answer: the correct answer for me was 0.464

Explanation: I divided 0.01044/0.0225 and the answer i got was 0.464

Answer 2

M₂ = 0.23 M

Step-by-step explanation:

Given data:

Volume of HNO₃ = 22.5 mL

Volume of NaOH = 31.27 mL

Molarity of NaOH = 0.167 M

Molarity of HNO₃ = ?

Solution:

M₁ = Molarity of NaOH

V₁ = Volume of NaOH

M₂ = Molarity of HNO₃

V₂ = Volume of HNO₃

M₁V₁ = M₂V₂

0.167 M × 31.27 mL = M₂ × 22.5 mL

5.2 M. mL = M₂ × 22.5 mL

M₂ = 5.2 M. mL /22.5 mL

M₂ = 0.23 M