Answer:
Therefore , the faster route distance is 13 miles.
Explanation:
Given:
AB = 5 miles to East
BC = 12 miles to South
To Find:
AC = Faster and Direct Route = ?
Solution:
Consider ΔABC as a Right Angle Triangle, hence By Pythagoras Theorem,
![(\textrm{Hypotenuse})^(2) = (\textrm{Shorter leg})^(2)+(\textrm{Longer leg})^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/w8aymum5euf0cartkdkt7ky9dclwpv3oy1.png)
Substituting the values we get
![(AC)^(2)=(AB)^(2)+(BC)^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/dkrnho3khrxoo3k8hfe3subczpev6q8au0.png)
![(AC)^(2)=5^(2)+12^(2)=169\\(AC)^(2)=169\\Square\ Rooting\\AC=√(169)=13\ miles](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2w7wje58gvslw28uydiqhumpw6aoppggk3.png)
Therefore , the faster route distance is 13 miles.