Question

What minimum frequency of light is needed to eject a photoelectron from atoms of of platinum, which require at least 9.08 x 10^-19 J/photon?

Answer 1

f = 1.37 × 10¹⁵ Hz

Step-by-step explanation:

Given data:

Energy of photon = 9.08 × 10⁻¹⁹ j

Frequency = ?

Solution:

Formula:

E = h. f

f = frequency

h = planck's constant

E = energy

Now we will put the values in formula.

h = 6.63 × 10⁻³⁴ j.s

9.08 × 10⁻¹⁹ j = 6.63 × 10⁻³⁴ j.s × f

f = 9.08 × 10⁻¹⁹ j / 6.63 × 10⁻³⁴ j.s

f = 1.37 × 10¹⁵ s⁻¹

s⁻¹ = Hz

f = 1.37 × 10¹⁵ Hz