Question

In Exercise, find the derivative of the function.
y = 32e0.23t

Answer 1

`y'=7.36e^(0.23t)`

Explanation:

`y=32e^(0.23t)`

take derivative with respect to t

`(dy)/(dt) =32(d(e^(0.23t)))/(dt)`

derivative of e^t is e^t

derivative of 0.23t is 0.23

`(dy)/(dt) =32 (d(e^(0.23t)))/(dt)`

Apply chain rule

`(dy)/(dt) =32(e^(0.23t))(0.23)`

`y'=7.36e^(0.23t)`