Answer:
0.991 grams of Nā are present in the flask
Step-by-step explanation:
Let's apply the Ideal gases Law to solve this:
P . V = n . R .T
Previously we have to convert Torr to atm (because the units of R, Universal Gases Constant). Let's think the rule of three:
760 Torr is 1 atm
19 Torr is (19 . 1)/ 760 = 0.025 atm
0.025 atm . 26L = n . 0.082 L.atm/mol.K . 224K
(0.025 atm . 26L) / (0.082 L.atm/mol.K . 224K) = 0.035 moles
Molar mass Nā = 28 g/m
Mol . molar mass = mass ā 0.035 m . 28 g/m = 0.991 grams