Answer:
1
Explanation:
Given: 15 decreased by six times a number is -9.
Lets assume the number be "x".
Now, putting the value in the equation to get the number.
six times a number = 6x
Then, 15 decreased by six times a number=
![(6x-15)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/b4p9mqivzalgqhbano0w22b2h8n5a5qt8g.png)
Now,
![(6x-15)= -9](https://img.qammunity.org/2021/formulas/mathematics/middle-school/o3jx1r3a4k3a97dx2oq0he7qsdoj4gadt1.png)
Adding both side by 15
⇒
⇒
![6x= 6](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zvhqr8unnc3avmol84nkfg8durv2k8dlwy.png)
Cross multiplying
∴ x=
![(6)/(6) = 1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/u9352n7i5nz43962b2t7n5qlsohr3u54yr.png)
Hence, the required number is 1.
Next subtituting the value in equation to check.
![(6x-15)= -9](https://img.qammunity.org/2021/formulas/mathematics/middle-school/o3jx1r3a4k3a97dx2oq0he7qsdoj4gadt1.png)
⇒
![(6* 1-15)= -9](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yx6tmgq4fwz98jphb3u57zivnwa61xx2wy.png)
⇒
![(6-15)= -9](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bg52nz1tzoama2by0k2d5t8yb3otrkrg1z.png)
∴
![-9= -9](https://img.qammunity.org/2021/formulas/mathematics/middle-school/83p0wivb0ccwrkywc1bte1q1f387uai33e.png)