Question

How many times a one pound (2.2 kg) block of iron can be split in half before it stops being iron.

Answer 1

Number of times a one pound (2.2 kg) block of iron can be split in half before it stops being iron

= 84.29 times

Step-by-step explanation:

Atoms : It is the smallest indivisible particle of the matter .

The atom can not be further breakdown .

Here in this question , we have to find the number of atoms (because it is the last possible situation for breaking of atom)

Mole : The quantity of the substance that contain as many particles as present in 12 g of C-12.It is quantity which Avogadro number(N0) of particles

`N_(0)=6.022* 10^(23)`

1.First calculate the number of moles of Fe in 2.2Kg Block

Mass of Iron (Fe) = 55.845 amu

Molar mass of Iron = 55.845 g

Given mass = 2.2 kg

1 kg = 1000 g

2.2 kg = 2200 g

`moles = (given\ mass)/(Molar\ mass)`

`Avogadro\ number = 6.022* 10^(23)`

moles = 39.39

`39.39 = (Number\ of\ Particles)/(N_(0))`

`Number\ of\ Particles=39.39* 6.022* 10^(23)`

`Number\ of\ Particles= 2.37* 10^(25)`

`2.37* 10^(25)` atoms

3.Calculate Number of time(n), the block is split into -Half

`2^(n)=2.37* 10^(25)`

Take log both side ,

`n\ log2 = log(2.37* 10^(25))`

Solve for n, you get

n= 84.29 (convert it to nearest whole number)

n = 84 times