Answer: The second derivative of the function is
![f''(x)=(1)/(2x)](https://img.qammunity.org/2021/formulas/mathematics/college/tluz406gv3084h46bcg5n3mwfydl3whobf.png)
Explanation:
Since we have given that
![f(x)=x\ln √(x)+2x](https://img.qammunity.org/2021/formulas/mathematics/college/mhzvg7iohwtlaux7xyvmlhh2yi2ps3aupl.png)
We need to find the second derivative of the function.
So, the first derivative would be
![f'(x)=1* \ln√(x)+x(1)/(√(x))* (1)/(2√(x))+2\\\\f'(x)=\ln √(x)+(1)/(2)+2\\\\f'(x)=\ln√(x)+(3)/(2)](https://img.qammunity.org/2021/formulas/mathematics/college/vu6xdbwuh3x5yu4dpze0dm8z7d9nexynne.png)
Now, second derivative would be
![f''(x)=(1)/(√(x))* (1)/(2√(x))\\\\f''(x)=(1)/(2x)](https://img.qammunity.org/2021/formulas/mathematics/college/nkawfc3jt3bdr53p8xvbphap7379j0twc4.png)
Hence, the second derivative of the function is
![f''(x)=(1)/(2x)](https://img.qammunity.org/2021/formulas/mathematics/college/tluz406gv3084h46bcg5n3mwfydl3whobf.png)