The distance walked by Larry is 9 miles and Camille is 18 miles and Simone is 7 miles
Solution:
Let "x" be the distance walked by Larry
Let "y" be the distance walked by Camille
Let "z" be the distance walked by Simone
At the end of the week they combined their distances and found that they walked 34 miles in total
Total distance = 34 miles
Therefore, we can say,
x + y + z = 34 ---------- eqn 1
Camille walked twice as far as Larry
distance walked by Camille = 2(distance walked by Larry)
y = 2x ---------- eqn 2
Larry walked 2 more miles than Simone
distance walked by Larry = 2 + distance walked by Simone
x = 2 + z
z = x - 2 ------- eqn 3
Substitute eqn 2 and eqn 3 in eqn 1
x + 2x + x - 2 = 34
4x - 2 = 34
4x = 34 + 2
4x = 36
x = 9
Substitute x = 9 in eqn 2
y = 2(9) = 18
y = 18
Substitute x = 9 in eqn 3
z = 9 - 2
z = 7
Thus distance walked by Larry is 9 miles and Camille is 18 miles and Simone is 7 miles