Answer:

Step-by-step explanation:
Given:
Let Floating Point to FP and the execution time of the FP = 70s
The total time of the CPU = 250s
Execution time of the Branch instruction = 40s
Execution time of the L/S instruction = 85s
Then, we have to decrease the FP instruction time.

Then, we have to find the total time required to run the program.



Finally, the percentage of the decreased total time.

