Answer:
Verified
Explanation:
Let A matrix be in the form of
![\left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/672so31hvv17yja5x20ajbepg9fn7hnrzo.png)
Then det(A) = ad - bc
Matrix A transposed would be in the form of:
![\left[\begin{array}{cc}a&c\\b&d\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/6iegjubqtkg9mzwc888ybhu5it5lxw7fdq.png)
Where we can also calculate its determinant:
det(AT) = ad - bc = det(A)
So the determinant of the nxn matrix is the same as its transposed version for 2x2 matrices