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Solve equation algebraically 3 root x-2x=-5

User BobiYo
by
8.5k points

1 Answer

6 votes

Answer:

The value of x is - 1 , - 6.25

Explanation:

Given linear equation as :

3
√(x) - 2 x = - 5

Rearranging the equation

3
√(x) = 2 x - 5

Taking square both side


(3√(x) )^(2) = (2 x - 5)²

Or, 9 x = 4 x² - 20 x + 25 [ from (a + b)² = a² + 2ab + b² ]

Or, 4 x² - 20 x - 9 x + 25 = 0

Or, 4 x² - 29 x + 25 = 0

The equation is in the form of quadratic equation i.e a x² + b x + c = 0

So, x =
\frac{- b\pm \sqrt{b^(2) - 4* a* c}}{2* a}

Or, x =
\frac{- (-29)\pm \sqrt{(-29)^(2) - 4* 4* 25}}{2* 4}

Or, x =
(- 29\pm √(841 - 400))/(8)

Or, x =
(- 29\pm √(441))/(8)

Or, x =
(-29+21)/(8) ,
(-29-21)/(8)

Or, x = - 1 , - 6.25

So, The value s of x = - 1 , - 6.25

Hence, The value of x is - 1 , - 6.25 Answer

User Harryscholes
by
8.6k points

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