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Given a Mendelian cross, use the rule of addition to calculate the probability that a particular F2 individual will be heterozygous.

User Erik Hart
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Answer:

The answer is 1/2.

Step-by-step explanation:

Using a Mendelian cross, the two possibilities for an offspring to become heterozygous is when a parent is heterozygous recessive and the other is heterozygous dominant or vice versa.

If the case is 1/2 heterozygous dominant x 1/2 heterozygous recessive then the offspring will have 1/4 dominant and recessive genotype.

If the case is 1/2 heterozygous recessive x 1/2 heterozygous dominant then the offspring will have 1/4 recessive and dominant genotype.

So the probability totally is 1/2.

I hope this answer helps.

User Bowserm
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