Question

A hot metal bolt of mass 0.06 kg and specific heat capacity 899 J/kg°C is dropped into a calorimeter containing 0.16 kg water at 20°C. The bolt and water reach a final temperature of 25°C.

What is the initial temperature of the bolt?

Answer 1

Step-by-step explanation:

Given

mass of hot metal
`m_1=0.06\ kg`

specific heat
`c=889\ J/kg-^(\circ)C`

mass of water
`m_2=0.16\ kg`

Temperature pf water
`T_2=20^(\circ)C`

Final Temperature
`T=25^(\circ)C`

let
`T_1` be the temperature of hot metal ball

Heat lost by heat metal bolt is gained by water in calorimeter

Heat lost by hot metal bolt
`Q_1=m* c* \Delta T`

`Q_1=0.06* 889* (T-25)`

Heat gained by water
`Q_2=m_2* c_w* \Delta T`

`Q_2=0.16* 4184* (25-20)`

`Q_1=Q_2`

`0.06* 889* (T-25)=0.16* 4184* (25-20)`

`T_1=25+62.75`

`T_1=87.75^(\circ)C`