Answer:
I= 0.40102036
Explanation:
∧ = raise to power
Given the equation
F(x) = √x² + 1.0
Now recalling the Taylor Series in respect to the approximation for degree n at x = a....
Therefore, it is given by :
f(x) = f(a) + f° (a) ((x - a)) + ( 1/2) f°° (a)((x -a)² + .....(1/n!) f∧n (a) ((x - a) ∧ n
Referring back to the Taylor Series
f(x) = - x ∧8/8 + x ∧ 4/2 + 1
If we integrate the Taylor series, we get,
f°(x) = - x ³*³/72 + x∧5/10 + x
At this point, we apply limit (lim) to the integrals
I = ∫ lim(0.4) (0) f(x) dx
I = ∫ (- x ∧8/8 + x ∧ 4/2 +1)dx
I = [ ( -x³*³/72 + x∧5/10 +x)]lim(0.4) lim(0)
The final answer then is:
I= 0.40102036