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Calculate the average value of an AC signal with a peak amplitude of 10V and a frequency of 10 kHz.

User Ramigg
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1 Answer

4 votes

Answer:

V(average)=6.37 V

Step-by-step explanation:

Given Data

Peak Voltage=10V

Frequency=10 kHZ

To Find

Average Voltage

Solution

For this first we need to find Voltage peak to peak

So

Voltage (peak to peak)= 2× voltage peak

Voltage (peak to peak)= 2×10

Voltage (peak to peak)= 20 V

Now from Voltage (peak to peak) formula we can find the Average Voltage

So

Voltage (peak to peak)=π×V(average)

V(average)=Voltage (peak to peak)/π

V(average)=20/3.14

V(average)=6.37 V

User Dotnetrocks
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