Question

A 0.34 kg ball is attached to the end of a cord of length 1.1 m. The ball is whirled in a circular path in a horizontal plane. The cord can withstand a maximum tension of 51.1 N before it breaks. What is the maximum speed the ball can have without the cord breaking?

Answer 1

12.86 m/s

Explanation:

Centripetal acceleartion formula:

`F=m.((v^(2) )/(r))\\`

`v=\sqrt{((F.r)/(m)) }\\`

`v = \sqrt{(51.1 N * 1.1 m)/(0.34 kg) } \\`

`v = 12.86 (m)/(s\\)\\`