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Emily has 12 fruits in her bowl. She has 3 apples, 5 bananas, 1 pear and 3 oranges. A fruit is selected at random. What is the probability that the fruit is an orange or a pear? A. 56 B. 23 C. 12 D. 13

User Csisanyi
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1 Answer

3 votes

Answer: The probability that the fruit is an orange or a pear is
(1)/(3) .

Explanation:

Given : Emily has 12 fruits in her bowl.

She has 3 apples, 5 bananas, 1 pear and 3 oranges.

A fruit is selected at random.

P(orange) =
\frac{\text{Number of oranges}}{\text{Total fruits}}


=(3)/(12)

P(pear)=
\frac{\text{Number of pears}}{\text{Total fruits}}


=(1)/(12)

Since both events of selecting orange and pear are mutually exclusive , so

The probability that the fruit is an orange or a pear = P(orange) + P(pear)


=(3)/(12)+(1)/(12)=(4)/(12)=(1)/(3)

Therefore , the probability that the fruit is an orange or a pear is
(1)/(3) .

User Keyur
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