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Verifying Properties of logarithms In Exercise,use a graphing utility to verify that the functions are equivalent for x > 0.

f(x) = In (x(x^2 + 1))1/2
g(x) = 1/2[In x + In(x^2 + 1)]

User Helmor
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Answer:

Considering the Product and the Power rule of the Logarithms, they're both equivalent for x >0

Explanation:

1) Considering the Product and the Power rule of the Logarithms:


\\log_(c)(ab)=log_(c)a+log_(c)b


\\log_(c)a^(b)=blog_(c)

2) Therefore we can say that:


\\f(x) = ln ((x)(x^2 + 1))^{(1)/(2)}\\\Rightarrow f(x)=ln (x(x^2 + 1))^{(1)/(2)}\Rightarrow f(x)=(1)/(2)ln((x)(x^(2) + 1)).\\g(x) = (1)/(2)(ln (x) + ln(x^(2) + 1))\Rightarrow g(x)=(1)/(2)ln(x(x^2+1))

Verifying Properties of logarithms In Exercise,use a graphing utility to verify that-example-1
User Redwan
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